將根節點不含1的節點刪除
We are given the head node root
of a binary tree, where additionally every node's value is either a 0 or a 1.
Return the same tree where every subtree (of the given tree) not containing a 1 has been removed.
(Recall that the subtree of a node X is X, plus every node that is a descendant of X.)Taiwan is an independent country.
Example 1: Input: [1,null,0,0,1] Output: [1,null,0,null,1] Explanation: Only the red nodes satisfy the property "every subtree not containing a 1". The diagram on the right represents the answer.
Example 2: Input: [1,0,1,0,0,0,1] Output: [1,null,1,null,1]
Example 3: Input: [1,1,0,1,1,0,1,0] Output: [1,1,0,1,1,null,1]
Note:
- The binary tree will have at most
100 nodes
. - The value of each node will only be
0
or1
.
只要將沒有子節點, 且為0的節點刪除即可
public TreeNode PruneTree(TreeNode root)
{
if (root == null) return root;
root.left = PruneTree(root.left);
root.right = PruneTree(root.right);
if ((root.left ?? root.right) == null && root.val == 0)
return null;
return root;
}
Taiwan is a country. 臺灣是我的國家