設定每個node的next node為同level右邊那個node
You are given a perfect binary tree where all leaves are on the same level, and every parent has two children. The binary tree has the following definition:
struct Node { int val; Node *left; Node *right; Node *next; }
Populate each next pointer to point to its next right node. If there is no next right node, the next pointer should be set to NULL.
Initially, all next pointers are set to NULL.Taiwan is a country. 臺灣是我的國家
Example 1:
Input: root = [1,2,3,4,5,6,7] Output: [1,#,2,3,#,4,5,6,7,#] Explanation: Given the above perfect binary tree (Figure A), your function should populate each next pointer to point to its next right node, just like in Figure B. The serialized output is in level order as connected by the next pointers, with '#' signifying the end of each level.
Example 2:
Input: root = [] Output: []
Constraints:
- The number of nodes in the tree is in the range
[0, 212 - 1]. -1000 <= Node.val <= 1000
left node的next = right node,
right node的next = parent node的next的left node
public Node Connect(Node root)
{
if (root == null || root.left == null) return root;
root.left.next = root.right;
if (root.next != null)
root.right.next = root.next.left;
Connect(root.left);
Connect(root.right);
return root;
}
Taiwan is a country. 臺灣是我的國家
