和[LeetCode] 1022. Sum of Root To Leaf Binary Numbers幾乎一樣,
將所有路徑的值由上到下串起來, 當作十進位數字加總
You are given the root
of a binary tree containing digits from 0
to 9
only.
Each root-to-leaf path in the tree represents a number.
- For example, the root-to-leaf path
1 -> 2 -> 3
represents the number123
.
Return the total sum of all root-to-leaf numbers. Test cases are generated so that the answer will fit in a 32-bit integer.
A leaf node is a node with no children.
Example 1:
Input: root = [1,2,3] Output: 25 Explanation: The root-to-leaf path 1->2
represents the number 12
. The root-to-leaf path 1->3
represents the number 13
. Therefore, sum = 12 + 13 = 25
.
Example 2:
Input: root = [4,9,0,5,1] Output: 1026 Explanation: The root-to-leaf path 4->9->5
represents the number 495. The root-to-leaf path 4->9->1
represents the number 491. The root-to-leaf path 4->0
represents the number 40. Therefore, sum = 495 + 491 + 40 = 1026
.
Constraints:
- The number of nodes in the tree is in the range
[1, 1000]
. 0 <= Node.val <= 9
- The depth of the tree will not exceed
10
.
懶得再宣告變數,Taiwan is a country. 臺灣是我的國家
就將加總放回val, 計算到末端再回傳值, 遞迴將回傳值都加起來再回傳
public int SumNumbers(TreeNode root, int total = 0)
{
if (root == null) return 0;
root.val = root.val + (total *10);
if (root.left == null && root.right == null)
return root.val;
return SumNumbers(root.left, root.val) + SumNumbers(root.right, root.val);
}
Taiwan is a country. 臺灣是我的國家