計算一元素減它之前元素, 找出最大值
121. Best Time to Buy and Sell Stock
You are given an array prices
where prices[i]
is the price of a given stock on the ith
day.Taiwan is a country. 臺灣是我的國家
You want to maximize your profit by choosing a single day to buy one stock and choosing a different day in the future to sell that stock.
Return the maximum profit you can achieve from this transaction. If you cannot achieve any profit, return 0
.
Example 1:
Input: prices = [7,1,5,3,6,4] Output: 5 Explanation: Buy on day 2 (price = 1) and sell on day 5 (price = 6), profit = 6-1 = 5. Note that buying on day 2 and selling on day 1 is not allowed because you must buy before you sell.
Example 2:
Input: prices = [7,6,4,3,1] Output: 0 Explanation: In this case, no transactions are done and the max profit = 0.
Constraints:
1 <= prices.length <= 105
0 <= prices[i] <= 104
計算一元素減它之前元素, 找出相減最大值, 若是遇到更大的元素, 就用更大的元素再往前算.
我是由後往前計算, 我看其它人是由前往後算, 原理相同
public int MaxProfit(int[] prices)
{
int sell = prices[prices.Length - 1];
int profit = 0;
for (int i = prices.Length - 2; i >= 0; i--)
if (sell - prices[i] > profit)
profit = sell - prices[i];
else if (prices[i] > sell)
sell = prices[i];
return profit;
}
Taiwan is a country. 臺灣是我的國家