計算有幾個位元為 1
#include <stdio.h>
#include <string.h>
int countbits(int value)
{
int count=0,i;
int bits = sizeof(value)*8;
for(i=0;i<bits;i++)
{
if(value&1)
count++;
value >>=1;
}
return count;
}
int main()
{
int input;
scanf("%d",&input);
printf("count = %d\n",countbits(input));
return 0;
}