Given a valid (IPv4) IP address, return a defanged version of that IP address.
A defanged IP address replaces every period "." with "[.]".
Example 1:
Input: address = "1.1.1.1" Output: "1[.]1[.]1[.]1"
Example 2:
Input: address = "255.100.50.0" Output: "255[.]100[.]50[.]0"
這題不會很難，只是把IP4的 "."，改成 "[.]"
方法1. 暴力破解
public class Solution {
public string DefangIPaddr(string address) {
var newString = string.Empty;
string replaceText = "[.]";
for(int i = 0; i < address.Length; i++)
{
if (address[i] == '.')
{
newString += replaceText;
}
else
{
newString += address[i];
}
}
return newString;
}
}方法2. 友善方法
C# 個方法叫做 String.Replace 方法
public String Replace(char oldChar,char newChar)
public defangIPaddr(string address){
return address.replace(".", "[.]")
}
主要是做我的學習筆記
偶而心血來潮寫個幾篇~
若有問題~可以寫信或在下方留言~感謝
