透過setContentView, 雖然可在layout之間轉換, 但仍然是使用同個Activity
透過setContentView, 雖然可在layout之間轉換, 但仍然是使用同個Activity
res\layout\layout1.xml
<TableLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent" >
<TextView
android:id="@+id/textView1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/layout1" />
<Button
android:id="@+id/btGo"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:onClick="onClick"
android:text="@string/go" />
</TableLayout>
res\layout\layout2.xml
<TableLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent" >
<TextView
android:id="@+id/textView1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/layout2" />
<Button
android:id="@+id/btBack"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:onClick="onClick"
android:text="@string/back" />
</TableLayout>
src\...\Activity1.java
package com.example.excercise3;
import android.os.Bundle;
import android.app.Activity;
import android.view.View;
public class Activity1 extends Activity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.layout1);
}
public void onClick(View v) {
switch(v.getId()){
case R.id.btGo:
setContentView(R.layout.layout2);
break;
case R.id.btBack:
setContentView(R.layout.layout1);
break;
}
}
}